Take 0.5g of sodium sulphate in a test tube and label it as A . Add 5ml water
In another test tube, take 0.5g of barium chloride, label it as B and add 5ml water
Transfer the solution from test tube A to the test tube B.
Mix the two solutions with gentle shaking.
Observe the white precipitate of barium sulphate.
Let the solution settle down and observe barium sulphate settling at the bottom
Take out excess water carefully using the dropper. Add dil sulphuric acid and shake
Double displacement reaction has taken place with formation of white precipitate of barium sulphate in the test tube. Barium sulphate is insoluble in dil sulphuric acid
When a solution of sodium sulphate is mixed with a solution of barium chloride, the following double displacement reaction takes place:
Na2SO4 (aq) + BaCl2 (aq) --> BaSO4 (s) + 2NaCl (aq)
In this reaction, sulphate ions (SO42- ) from sodium sulphate are displaced by chloride ions (Cl-) and chloride ions in barium chloride are displaced by sulphate ions. As a result, a white precipitate of barium sulphate is formed and sodium chloride remains in the solution.